T\u1ed5ng h\u1ee3p m\u1eb9o b\u1eaft l\u00f4 \u0111\u1ec1 theo k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc chu\u1ea9n nh\u1ea5t t\u1eeb tr\u01b0\u1edbc \u0111\u1ebfn. Tr\u00ean \u0111\u00e2y t\u1ed5n nay cho anh em tham kh\u1ea3o \u0111\u01b0\u1ee3c c\u00e1ch b\u1eaft s\u1ed1 theo KQXS MB \u0111\u1ec3 c\u00f3 th\u1ec3 \u0111\u01b0a ra m\u1ed9t l\u1ef1a ch\u1ecdn t\u00ecm ki\u1ebfm con s\u1ed1 h\u00e0ng ng\u00e0y d\u1ec5 v\u1ec1 nh\u1ea5t theo c\u00e1c bi\u1ec7n ph\u00e1p soi c\u1ea7u \u0111\u1eb7c bi\u1ec7t, thong ke lo to, ch\u1ea1m cau dac biet li\u00ean ti\u1ebfp nhanh nh\u1ea5t v\u1edbi c\u00e1c thanh vi\u00ean v\u00e0 chuy\u00ean gia v\u1ec1 x\u1ed5 s\u1ed1. C\u00f9ng \u0111i\u1ec3m qua m\u1ed1t s\u1ed1 m\u1eb9o b\u1eaft l\u00f4 \u0111\u1ec1 mi\u1ec1n b\u1eafc hi\u1ec7u qu\u1ea3 nh\u1ea5t. \u0110\u1eb7c bi\u1ec7t \u0111\u00e2y l\u00e0 nh\u1eefng b\u00ed quy\u1ebft soi c\u1ea7u MB b\u1ecb gi\u1ea5u k\u00edn l\u00e2u nay. \u0110\u1eebng b\u1ecf l\u1ee1 c\u01a1 h\u1ed9i gi\u00e0nh chi\u1ebfn th\u1eafng v\u1edbi c\u00e1c chia s\u1ebd d\u01b0\u1edbi \u0111\u00e2y nh\u00e9 ! 9 m\u1eb9o soi c\u1ea7u b\u1eaft l\u00f4 Mi\u1ec1n B\u1eafc c\u1ea7n bi\u1ebft \u0111\u1ec3 th\u1eafng<\/span><\/p>\n C\u1ea7u n\u00e0y \u0103n \u1ed5n \u0111\u1ecbnh 9\/10 tu\u1ea7n li\u1ec1n. Con s\u1ed1 gi\u1eefa gi\u1ea3i nh\u1ea5t ng\u00e0y ch\u1ee7 nh\u1eadt tu\u1ea7n th\u1ee9 nh\u1ea5t \u0111\u00e1nh \u0111\u1ebfn th\u1ee9 7 tu\u1ea7n ti\u1ebfp theo. <\/span><\/p>\n V\u00ed d\u1ee5:<\/p>\n Ch\u1ee7 Nh\u1eadt-31\/3 c\u00f3 gi\u1ea3i nh\u1ea5t 97211 \u2013> T3=25,T5=22<\/p>\n Ch\u1ee7 Nh\u1eadt-07\/4 c\u00f3 gi\u1ea3i nh\u1ea5t 39855 \u2013>> T5=98, T6=84<\/p>\n Ch\u1ee7 Nh\u1eadt-14\/4 c\u00f3 gi\u1ea3i nh\u1ea5t 35501 \u2013>> T6=54<\/p>\n M\u1eb9o 2 : C\u1ea7u ch\u1ea1m s\u1ed1<\/p>\n L\u1ea5y t\u1ed5ng c\u1ee7a \u0111\u1ec1 ng\u00e0y CN gh\u00e9p v\u1edbi s\u1ed1 \u0111u\u00f4i c\u1ee7a \u0111\u1ec1 ng\u00e0y th\u1ee9 s\u00e1u (tu\u1ea7n th\u01b0 nh\u1ea5t) th\u00e0nh b\u1ed9 s\u1ed1 \u0111\u00e1nh t\u1eeb th\u1ee9 2 \u0111\u1ebfn h\u1ebft tu\u1ea7n tu\u1ea7n ti\u1ebfp theo. C\u1ea7u n\u00e0y ch\u1ea1y kh\u00e1 \u0111\u1ec1u c\u1ee9 \u0103n kho\u1ea3ng 3->4 tu\u1ea7n th\u00ec ngh\u1ec9 1->2 tu\u1ea7n:<\/span><\/p>\n V\u00ed d\u1ee5: + Th\u1ee9 6 ng\u00e0y 29\/3 c\u00f3 \u0111\u1ec1 l\u00e0 50 Ch\u1ee7 Nh\u1eadt ng\u00e0y 31\/3 c\u00f3 \u0111\u1ec1 l\u00e0 38 = t\u1ed5ng 1 ==>> B\u1ed9 01 \u2013>>> \u0110\u1ec1 ng\u00e0y 01\/9 \u0111\u00e3 n\u1ed5 60. + Th\u1ee9 6 ng\u00e0y 05\/4 c\u00f3 \u0111\u1ec1 l\u00e0 78 Ch\u1ee7 Nh\u1eadt ng\u00e0y 07\/4 c\u00f3 \u0111\u1ec1 l\u00e0 11 = t\u1ed5ng 2==>>B\u1ed9 23 \u2013>>> \u0110\u1ec1 ng\u00e0y 15\/9 \u0111\u00e3 n\u1ed5 32 + Th\u1ee9 6 ng\u00e0y 12\/4 c\u00f3 \u0111\u1ec1 l\u00e0 84 Ch\u1ee7 Nh\u1eadt ng\u00e0y 14\/4 c\u00f3 \u0111\u1ec1 l\u00e0 39 = t\u1ed5ng 12 ==>>B\u1ed9 14, 24 \u2013>>> Tu\u1ea7n n\u00e0y ngh\u1ec9<\/span><\/p>\n L\u1ea5y t\u1ed5ng gi\u1ea3i \u0110B ng\u00e0y CN tu\u1ea7n n l\u00e0m b\u1ed9 \u0111\u1ec1 \u0111\u00e1nh \u0111\u1ebfn h\u1ebft tu\u1ea7n \u0111\u00f3. C\u1ea7u n\u00e0y \u0103n 3-5 tu\u1ea7n r\u1ed3i ngh\u1ec9 2-3 tu\u1ea7n r\u1ed3i m\u00fac t\u00edp.<\/span><\/p>\n <\/p>\n L\u1ea5y 2 s\u1ed1 \u0111\u1ea7u ti\u00ean c\u1ee7a gi\u1ea3i nh\u1ea5t c\u1ee7a ng\u00e0y th\u1ee9 2 tu\u1ea7n th\u1ee9 nh\u1ea5t l\u00e0m b\u1ed9 s\u1ed1 \u0111\u1ec3 \u0111\u00e1nh \u0111\u1ebfn th\u1ee9 2 tu\u1ea7n ti\u1ebfp theo. C\u1ea7u n\u00e0y \u0103n r\u1ea5t \u0111\u1ec1u, c\u1ee9 \u0103n 4-7 tu\u1ea7n th\u00ec ngh\u1ec9 1-2 tu\u1ea7n r\u1ed3i \u0103n ti\u1ebfp. V\u00ec v\u1eady khi th\u1ea5y hi\u1ec7n t\u01b0\u1ee3ng b\u1eaft c\u1ea7u qu\u1ea5t m\u1ea1nh s\u1ed1.<\/span><\/p>\n V\u00ed d\u1ee5: Th\u1ee9 2-01\/9 c\u00f3 gi\u1ea3i nh\u1ea5t 32203 \u2013> l\u1ea5y 32 l\u00e0m b\u1ed9 \u0111\u1ec1 ==> 5\/9 n\u1ed5 78 Th\u1ee9 2-08\/9 c\u00f3 gi\u1ea3i nh\u1ea5t 87873 \u2013> l\u1ea5y 78 l\u00e0m b\u1ed9 \u0111\u1ec1 ==> 15\/9 n\u1ed5 32 Th\u1ee9 2-15\/9 c\u00f3 gi\u1ea3i nh\u1ea5t 15381 \u2013> l\u1ea5y 15 l\u00e0m b\u1ed9 \u0111\u1ec1 ==> 17\/9 n\u1ed5 06, ng\u00e0y 20\/9 n\u1ed5 01 Th\u1ee9 2-22\/9 c\u00f3 gi\u1ea3i nh\u1ea5t 27444 \u2013> l\u1ea5y 27 l\u00e0m b\u1ed9 \u0111\u1ec1 ==> C\u00f3 th\u1ec3 \u0111\u1ec1 v\u1ec1 k\u00e9p 22, 77, 272 ( Tu\u1ea7n t\u1eeb 23\/9 \u0111\u1ebfn 29\/9 c\u00f3 th\u1ec3 \u0111\u1ec1 v\u1ec1 k\u00e9p 22, 77, 272 \u2013 ch\u00fa \u00fd ch\u00fa \u00fd )<\/span><\/p>\n C\u00e1i n\u00e0y gi\u00fap th\u1ed1ng k\u00ea l\u00f4 \u0111\u01b0\u1ee3c ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn \u0111\u01b0\u1ee3c 1 s\u1ed1 s\u1ebd tham gia v\u00e0o ch\u01a1i \u0111\u1ec1. L\u1ea5y 2 s\u1ed1 gi\u1ea3i 7 cu\u1ed1i c\u00f9ng l\u00e0m s\u1ed1 \u0111\u1ec3 ch\u1ea1m c\u1ea7u. \u2013 \u0102n li\u1ec1n ng\u00e0y; th\u00f4ng th\u01b0\u1eddng 2-4 ng\u00e0y li\u00ean ti\u1ebfp V\u00ed d\u1ee5: 3 ng\u00e0y 18, 19, 20\/9 \u0111\u1ec1u l\u1ea5y 1 s\u1ed1 cu\u1ed1i gi\u1ea3i 7. \u2013 \u0102n c\u00e1ch ng\u00e0y th\u00ec c\u1ea7u d\u00e0i h\u01a1n 5-8 ng\u00e0y (ho\u1eb7c ch\u1ec9 \u0103n v\u00e0o ng\u00e0y ch\u1eb5n or nh\u1eefng ng\u00e0y l\u1ebb).<\/span><\/p>\n V\u00ed d\u1ee5: 18\/8-gi\u1ea3i 7 l\u00e0 31 \u2013> \u0111\u1ec1 19\/8 n\u1ed5 38 20\/8-gi\u1ea3i 7 l\u00e0 82 \u2013> \u0111\u1ec1 21\/8 n\u1ed5 27 22\/8-gi\u1ea3i 7 l\u00e0 90 \u2013> \u0111\u1ec1 23\/8 n\u1ed5 20 \u2026\u2026.t\u01b0\u01a1ng t\u1ef1 cho c\u00e1c ng\u00e0y sau\u2026\u2026<\/span><\/p>\n Theo c\u00e1ch th\u1ee9c ch\u1ea1m c\u1ea7u n\u00e0y th\u00ec ng\u00e0y n\u00e0o c\u0169ng ch\u1ea1m \u00edt nh\u1ea5t 1 s\u1ed1. Anh em c\u1ee9 test th\u1eed m\u00e0 xem s\u1ebd th\u1ea5y hi\u1ec7u qu\u1ea3.<\/p>\n <\/p>\n Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y s\u1ebd th\u1ed1ng k\u00ea \u0111\u01b0\u1ee3c t\u1ed5ng c\u00e1c c\u1eb7p \u0111\u00e3 ra theo t\u1eebng ng\u00e0y h\u00f4m \u0111\u00f3 cho ra con s\u1ed1 ch\u1ed1t \u0111\u1eb9p nh\u1ea5t trong ng\u00e0y ti\u1ebfp theo d\u1ef1a v\u00e0o c\u00e1c ket qua xo so mien bac nhanh nhat hom do.<\/p>\n Th\u1ed1ng k\u00ea nh\u1eefng t\u1ed5ng \u0111\u00e3 ra c\u1ee7a tu\u1ea7n tr\u01b0\u1edbc \u0111\u00f3 :<\/p>\n Nh\u01b0 sau: Theo d\u00f5i \u0110\u1ec1 ra tu\u1ea7n t\u1eeb 14->20 ta c\u00f3 ket qua xo so mien bac c\u1ee7a T\u1ed5ng 2 v\u00e0 T\u1ed5ng 3 l\u00e0 11 v\u00e0 06, nh\u01b0 v\u1eady l\u00e0 c\u00f2n l\u1ea1i 2 3 4 5 7 8 9 ta s\u1ebd gh\u00e9p v\u00e0o \u0111\u01b0\u1ee3c:<\/p>\n Nh\u01b0 v\u1eady k\u1ebft qu\u1ea3 trong tu\u1ea7n \u0111\u00f3 c\u00f3 83 48 v\u00e0 28.<\/p>\n Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y \u0111\u01b0\u1ee3c coi l\u00e0 b\u00ed k\u00edp anh em n\u00e0o b\u1eaft \u0111\u01b0\u1ee3c coi nh\u01b0 th\u1ea7n b\u00e0i c\u1ee7a ket qua xo so mien bac <\/span><\/p>\n Anh em s\u1ebd theo d\u00f5i b\u1ea3ng k\u1ebft qu\u1ea3 n\u1ebfu th\u1ea5y \u1edf 3 gi\u1ea3i li\u1ec1n nhau c\u00f3 2 s\u1ed1 X-Y x\u1ebfp theo h\u00ecnh qu\u1ea3 tr\u00e1m th\u1ebf n\u00e0y: V\u00ed d\u1ee5 cho n\u00f3 sinh \u0111\u1ed9ng: Ng\u00e0y 20\/3\/214, t\u1ea1i gi\u1ea3i 3 c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng nh\u01b0 sau: xx2xx x525x xx2xx ===> Ng\u00e0y 21\/3 n\u1ed5 l\u00f4 25 hai nh\u00e1y.<\/span><\/p>\n Ng\u00e0y 03\/04\/2014, T\u1ea1i gi\u1ea3i n\u0103m, s\u00e1u, b\u1ea3y c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng nh\u01b0 sau:<\/p>\n 42<\/p>\n 929<\/p>\n 9210 = = =>2=Y,9=X. = => YX = => 29. C\u00f3 x\u1ea3y ra ng\u00e0y 04 ho\u1eb7c 5 th\u00e1ng 04?<\/p>\n Ng\u00e0y 31\/3\/2014, t\u1ea1i gi\u1ea3i b\u1ed1n, n\u0103m c\u00f3 hi\u1ec7n t\u01b0\u1ee3ng:<\/p>\n x2xx<\/p>\n 323x<\/p>\n x2xx ===> Ng\u00e0y 02\/9 n\u1ed5 lu\u00f4n l\u00f4 23 hai nh\u00e1y<\/p>\n N\u00f3i chung hi\u1ec7n t\u01b0\u1ee3ng n\u00e0y r\u1ea5t \u00edt khi g\u1eb7p (1 th\u00e1ng ch\u1ec9 c\u00f3 1-2 l\u1ea7n) v\u00ec v\u1eady khi th\u1ea5y hi\u1ec7n t\u01b0\u1ee3ng n\u00e0y l\u00e0 qu\u1ea5t s\u1ed1 lu\u00f4n.<\/p>\n \u0110\u1ec1 n\u1ed5 54 v\u00e0 \u0110\u1ec1 n\u1ed5 26 14\/9 gi\u1ea3i \u0110B: 07439 = T\u1ed5ng 23 \u2013 8 = 15 l\u1ea5y 5 l\u00e0m \u0111\u1ea7u \u0111u\u00f4i v\u00e0 \u0111\u1ec1 n\u1ed5 25, 22 07\/9 gi\u1ea3i \u0110B: 25511 = T\u1ed5ng 14 \u2013 8 = 06 l\u1ea5y 6 l\u00e0m \u0111\u1ea7u \u0111\u00edt.<\/span><\/p>\n Soi b\u1ea3ng \u0111\u1ec1 tu\u1ea7n l\u1ea5y : T\u1ed5ng gi\u1ea3i \u0110B ng\u00e0y Ch\u1ee7 Nh\u1eadt (tu\u1ea7n \u0111\u1ea7u) tr\u1eeb \u0111i 8, l\u1ea5y s\u1ed1 \u0111u\u00f4i c\u1ee7a k\u1ebft qu\u1ea3 l\u00e0m \u0111\u1ea7u \u0111\u00edt \u0111\u00e1nh trong tu\u1ea7n t\u1eeb th\u1ee9 2 \u0111\u1ebfn h\u1ebft Ch\u1ee7 Nh\u1eadt (tu\u1ea7n ti\u1ebfp theo).C\u1ea7u n\u00e0y \u0103n \u0111\u1ec1u l\u1eafm 8 tu\u1ea7n li\u1ec1n. \u00c1p d\u1ee5ng BK n\u00e0y \u0111\u00e1nh \u0111\u1ea7u \u0111\u00edt trong tu\u1ea7n l\u00e0 OK.<\/span><\/p>\n V\u00ed d\u1ee5: 31\/8 gi\u1ea3i \u0110B: 50483 = T\u1ed5ng 20 \u2013 8 = 12 l\u1ea5y 2 l\u00e0m \u0111\u1ea7u \u0111\u00edt \u0111\u1ec1 n\u1ed5 x7x\u00e021\/9 gi\u1ea3i \u0110B: 63727 = T\u1ed5ng 25 \u2013 8 = 17 l\u1ea5y 7 l\u00e0m \u0111\u1ea7u \u0111u\u00f4i \u0110\u00e3 n\u1ed5 73 v\u00e0o ng\u00e0y 25\/9<\/span><\/p>\n Soi b\u1ea3ng \u0111\u1ec1 tu\u1ea7n l\u1ea5y con gi\u1eefa gi\u1ea3i \u0110B c\u1ee7a ng\u00e0y th\u1ee9 t\u01b0, \u0111\u00e1nh t\u1eeb th\u1ee9 5 \u0111\u1ebfn CN. C\u1ea7u n\u00e0y \u0103n kh\u00e1 \u0111\u1ec1u.<\/span><\/p>\n V\u00ed d\u1ee5: 03\/9 gi\u1ea3i \u0110B: 13258, \u0111\u1ebfn ng\u00e0y 04\/9 \u0111\u1ec1 n\u1ed5 22 10\/9 gi\u1ea3i \u0110B: 85414, \u0111\u1ebfn ng\u00e0y 12\/9 \u0111\u1ec1 n\u1ed5 84, ng\u00e0y 13\/9 n\u1ed5 44 17\/9 gi\u1ea3i \u0110B: 99506, \u0111\u1ebfn ng\u00e0y 19\/9 n\u1ed5 lu\u00f4n \u0111\u1ec1 54.<\/p>\n \u0110\u1ebfn \u0111\u00e2y coi nh\u01b0 t\u1ea1m k\u1ebft th\u00fac, v\u1edbi nh\u1eefng c\u00e1ch b\u1eaft l\u00f4 theo KQXS mi\u1ec1n b\u1eafc n\u00e0y \u0111\u1ee7 cho anh em \u0111\u00e1nh m\u00e3i kh\u00f4ng h\u1ebft. Ch\u00fac anh em may m\u1eafn nh\u00e9!<\/p>\n Ti\u1ebfp t\u1ee5c ch\u00fang ta s\u1ebd ti\u1ebfp t\u1ee5c v\u1edbi ph\u01b0\u01a1ng ph\u00e1p \u0111\u00e1nh d\u00e0n \u0111\u1eb7c bi\u1ec7t ch\u00ednh x\u00e1c.!! anh em ch\u1edd nh\u00e9.<\/p>\n<\/div>\nM\u1eb9o 1: C\u1ea7u ch\u1ea1m s\u1ed1 1 kh\u00f4ng th\u1ec3 b\u1ecf<\/span><\/h3>\n
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\n<\/span><\/p>\nM\u1eb9o 3 : C\u1ea7u ch\u1ea1m s\u1ed1 3<\/span><\/h3>\n
\n<\/span><\/p>\nM\u1eb9o 4: C\u1ea7u ch\u1ea1m s\u1ed1 4<\/span><\/h3>\n
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\n<\/span><\/p>\nM\u1eb9o 5 : Ph\u01b0\u01a1ng ph\u00e1p ch\u1ea1m gi\u1ea3i 7<\/span><\/h3>\n
\nC\u00e1ch th\u1ee9c:<\/span><\/p>\n
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\n<\/span><\/p>\nL\u1ea5y 3 gi\u1ea3i 7 \u1edf tr\u00ean:<\/span><\/h4>\n
M\u1eb9o 6: Ph\u01b0\u01a1ng ph\u00e1p \u0111\u00e1nh \u0111\u1ec1 d\u00e0n trong tu\u1ea7n<\/span><\/h3>\n
T\u1ed5ng thi\u1ebfu:<\/span><\/h4>\n
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Lo\u1ea1i tr\u1eeb t\u1ed5ng 2 v\u00e0 t\u1ed5ng 3.<\/span><\/h4>\n
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M\u1eb9o 7 : B\u00ed k\u00edp B\u1ea1ch th\u1ee7 l\u00f4 th\u1ea7n ch\u01b0\u1edfng<\/span><\/h3>\n
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\nY
\nX Y X
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\nth\u00ec fang c\u1ea3 th\u1ed5 c\u01b0 lu\u00f4n con l\u00f4 b\u1ea1ch th\u1ee7 YX trong 2 ng\u00e0y sau \u0111\u00f3.<\/p>\n
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\n<\/span><\/p>\nM\u1eb9o 8 : C\u1ea7u ch\u1ea1m \u0111\u1ec1 s\u1ed1 9<\/span><\/h3>\n
M\u1eb9o 9 : C\u1ea7u ch\u1ea1m \u0111\u1ec1 s\u1ed1 11<\/span><\/h3>\n
c\u1ea7u vip \u0103n ngay<\/span><\/h3>\n